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sashafilipp854
@sashafilipp854
June 2022
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. Сколько граммов этилена должно вступить в реакцию с водородом, чтобы образовалось 5 г/моль этана.
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egorkaego2014
C2H4 +H2= C2H6
n(C2H6)= m\M=5\30=0,17 моль
nC2H6=nC2H4=0,17 моль
mC2H4 =M*n=28*0,17=4,7г
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Answers & Comments
n(C2H6)= m\M=5\30=0,17 моль
nC2H6=nC2H4=0,17 моль
mC2H4 =M*n=28*0,17=4,7г