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amaykovska03
@amaykovska03
June 2022
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AlCL3 m,г-26,7 M,г/моль-? n,моль -? N,частинок-?
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nikolaygr
Verified answer
M(AICI3)=26,7г
M(AICI3)=133,5г/моль
n(AICI3)=26,7/133,5=0,2моль
N(AICI3)=0,2*6,02*10²³=1,204*10²³молекул
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Answers & Comments
Verified answer
M(AICI3)=26,7гM(AICI3)=133,5г/моль
n(AICI3)=26,7/133,5=0,2моль
N(AICI3)=0,2*6,02*10²³=1,204*10²³молекул