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nastyushaemeli
@nastyushaemeli
October 2021
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асчитайте тепловой эффект реакции горения аммиака в кислороде с образованием малекулярного азота и воды,зная энергии связей веществ,участвующих в
реакциях NH3-1161. O2-492. N2-942. H2O-919кДж/моль
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Nadyamoiseeva20
4NH3 +3О2 = 2
N2 +6 Н2О
ΔН= (1161кДж*4 + 492кДж*3)-(942кДж*2 +919кДж*6) = (4644 +1476 )-(1884+5514) = -1278кДж
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Answers & Comments
ΔН= (1161кДж*4 + 492кДж*3)-(942кДж*2 +919кДж*6) = (4644 +1476 )-(1884+5514) = -1278кДж