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RoDgEr7
@RoDgEr7
July 2022
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СРОЧНО ПОМОГИТЕ!!!!!!
Установите формулу одноосновной карбоновое кислоаты, молярная масса которой равна 102 г/моль
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bektosh9915mailru
CnH2n+1 -COOH
12+2n+1+12+16+16+1=102г/моль
14n+46= 102г/моль
14n = 102-46
14n= 56
n=56/14
n= 4
отсюда
CnH2n+1-COOH
n=4
C4H9COOH
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Answers & Comments
12+2n+1+12+16+16+1=102г/моль
14n+46= 102г/моль
14n = 102-46
14n= 56
n=56/14
n= 4
отсюда
CnH2n+1-COOH
n=4
C4H9COOH