Ответ:
дано
W(C) = 85.7 % = 0.857
D(H2) = 21
-------------------------
CxHy-?
W(H) = 1 - 0.857 = 0.143
M(CxHy) = D(H2) * 2 = 21*2 = 42 g/mol
n(C) = 0.857 * 42 / 12 = 3
n(H) = 0.143 * 42 / 1 = 6
n(C) : n(H) = 3:6
C3H6
ответ С3Н6
Объяснение:
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Ответ:
дано
W(C) = 85.7 % = 0.857
D(H2) = 21
-------------------------
CxHy-?
W(H) = 1 - 0.857 = 0.143
M(CxHy) = D(H2) * 2 = 21*2 = 42 g/mol
n(C) = 0.857 * 42 / 12 = 3
n(H) = 0.143 * 42 / 1 = 6
n(C) : n(H) = 3:6
C3H6
ответ С3Н6
Объяснение: