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shkolnikc228
@shkolnikc228
September 2021
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Найти массу 24 * 1023 молекул озона.
Дано Формулы Решение
О3 m = M * n n = 24 *1023/6 *1023 = 4 моль
N = 24 * 1023 молекул n = N/NA M(O3) = 48 г/моль
m = ? m = 48 *4 = 192 г
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