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fyvapro95
@fyvapro95
October 2021
1
14
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Молю о помощи! Пожалуйста, помогите
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alfabetta
2(sin(π/9-sin(8π/9))-3sin(8π/9) =
3cos(29π/18)+3(cos(29π/18)-cos(7π/18))
2*2
sin((π/9-8π/9)/2)*
cos((π/9+8π/9)/2)-
3sin(8π/9) =
3cos(29π/18)+3 (-2)sin((29π/18+7π/18)/2)*cos((29π/18-7π/18)/2)
4*
sin(-7π/18)*
cos(π/2)
-
3sin(8π/9) =
3cos(29π/18)-6sin(π)*cos(11π/18)
4*
sin(-7π/18)*0
-
3sin(8π/9) =
3cos(29π/18)-6*0*cos(11π/18)
-
3sin(8π/9) =
3cos(29π/18)
-sin((9
π
-π)/9) =
-sin(π-π/9) =
-sin(π/9) =
-sin(π/9) =
cos(18π+11π/18)) cos(π+11π/18) cos(11π/18) cos((9π+2π)/18)
-sin(π/9) =
-sin(π/9) =
-1
cos(π/2+π/9) sin(π/9)
4 votes
Thanks 1
fyvapro95
Я уже сам решил, спасибо, но Вы все равно восхитительны :)
Благодарю!
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Answers & Comments
3cos(29π/18)+3(cos(29π/18)-cos(7π/18))
2*2sin((π/9-8π/9)/2)*cos((π/9+8π/9)/2)-3sin(8π/9) =
3cos(29π/18)+3 (-2)sin((29π/18+7π/18)/2)*cos((29π/18-7π/18)/2)
4*sin(-7π/18)*cos(π/2)-3sin(8π/9) =
3cos(29π/18)-6sin(π)*cos(11π/18)
4*sin(-7π/18)*0-3sin(8π/9) =
3cos(29π/18)-6*0*cos(11π/18)
-3sin(8π/9) =
3cos(29π/18)
-sin((9π-π)/9) = -sin(π-π/9) = -sin(π/9) = -sin(π/9) =
cos(18π+11π/18)) cos(π+11π/18) cos(11π/18) cos((9π+2π)/18)
-sin(π/9) = -sin(π/9) = -1
cos(π/2+π/9) sin(π/9)
Благодарю!