Ответ:
Объяснение: 1) sin(π/8) > sin(-π/8); Потому что sin(π/8)>0, а sin(-π/8)=
=-sin(π/8) < 0;
2) tg(-4) = (-tg4); бо tg(-4)= -tg4;
3) cos(-π/10) > (-cos(π/12), потому что cos(-π/10)=cos(π/10) > 0, a
-cos(/12) < 0;
4) sin(-π/3) + cos(-π/6) + tg(-π/4) = -sin(π/3) + cos(π/6) - tg(π/4)=
=-√3/2 + √3/2 - 1 = -1.
5) cos(-π/4) - sin(-π/4) - tg(-π) = cos(π/4) - sin(-π/4) - (-tg(-π))=
=(√2)/2 + (√2)/2 +0 = (2√2)/2=√2.
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Answers & Comments
Ответ:
Объяснение: 1) sin(π/8) > sin(-π/8); Потому что sin(π/8)>0, а sin(-π/8)=
=-sin(π/8) < 0;
2) tg(-4) = (-tg4); бо tg(-4)= -tg4;
3) cos(-π/10) > (-cos(π/12), потому что cos(-π/10)=cos(π/10) > 0, a
-cos(/12) < 0;
4) sin(-π/3) + cos(-π/6) + tg(-π/4) = -sin(π/3) + cos(π/6) - tg(π/4)=
=-√3/2 + √3/2 - 1 = -1.
5) cos(-π/4) - sin(-π/4) - tg(-π) = cos(π/4) - sin(-π/4) - (-tg(-π))=
=(√2)/2 + (√2)/2 +0 = (2√2)/2=√2.