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СAm1
@СAm1
July 2022
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Mr Ca3 (PO4)3 помогите решить пожалуйста )))))
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Tizifona
Verified answer
Мr(Ca3(PO4)2) = (40 * 3) + (31 * 2) + (16 * 4 * 2) = 120 + 62 + 128 = 310 г/моль
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Verified answer
Мr(Ca3(PO4)2) = (40 * 3) + (31 * 2) + (16 * 4 * 2) = 120 + 62 + 128 = 310 г/моль