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linn98
@linn98
July 2022
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(n-2)!/(n-4)!=(n-2)(n-3) уравнение факториал
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sedinalana
Verified answer
(n-4)!(n-3)(n-2)/(n-4)!=(n-2)(n-3)
(n-3)(n-2)=(n-2)(n-3)
n∈(4;∞)
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Verified answer
(n-4)!(n-3)(n-2)/(n-4)!=(n-2)(n-3)(n-3)(n-2)=(n-2)(n-3)
n∈(4;∞)