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8m3 + n6 = (__ m/n + n^_)(__m^2 – 2mn2 + n^__).
8m3 + n6 = (__ m/n + n^_)(__m^2 – 2mn2 + n^__).
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Ответ:
Объяснение:
8m³+n^6=(2m)³+(n²)³= (2m+n²)((2m)²-2mn²+(n²)² =
=(2m+n²)(4m²-2mn^2+n^4)