Выражение: 52root(n^4/8*m^2):52root(4*m^2/n)
Ответ: n^(1//13)/52root8/52root4*52rootn
Решаем по действиям:1. 52root(n^4/8*m^2)=n^(1//13)/52root8*m^(1//26) 52root(n^4/8*m^2)=52root(n^4)/52root8*52root(m^2) 1.1. 52root(n^4)=n^(1//13) 1.2. 52root(m^2)=m^(1//26)2. 52root(4*m^2/n)=52root4*m^(1//26)/52rootn3. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn)=n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn4. m^(1//26)/m^(1//26)=1
Решаем по шагам:1. n^(1//13)/52root8*m^(1//26):52root(4*m^2/n) 1.1. 52root(n^4/8*m^2)=n^(1//13)/52root8*m^(1//26) 52root(n^4/8*m^2)=52root(n^4)/52root8*52root(m^2) 1.1.1. 52root(n^4)=n^(1//13) 1.1.2. 52root(m^2)=m^(1//26)2. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn) 2.1. 52root(4*m^2/n)=52root4*m^(1//26)/52rootn3. n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn 3.1. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn)=n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn4. n^(1//13)/52root8/52root4*52rootn 4.1. m^(1//26)/m^(1//26)=1
Приводим к окончательному ответу с возможной потерей точности:
Окончательный ответ: n^0.0769230769230769/1.06891997265126*52rootn
По действиям: 1. 1//13~~0.0769230769230769 1.00|1_3_ _ 9_1_|0.0769230769230769 90 7_8_ 120 1_1_7_ 30 2_6_ 40 3_9_ 100 9_1_ 90 7_8_ 120 1_1_7_ 30 2_6_ 40 3_9_ 100 9_1_ 90 7_8_ 120 1_1_7_ 3 2. 52root8=1.04079959637863 3. 52root4=1.02701805070877 4. 1.04079959637863*1.02701805070877~~1.06891997265126 X1.04079959637863 _ _ _ _ _ _ _ _ _ _ _ _ _ _1_._0_2_7_0_1_8_0_5_0_7_0_8_7_7_ _ 728559717465041 728559717465041 832639677102904 000000000000000 728559717465041 000000000000000 520399798189315 000000000000000 832639677102904 104079959637863 000000000000000 728559717465041 208159919275726 000000000000000 1_0_4_0_7_9_9_5_9_6_3_7_8_6_3_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 1.0689199726512551741967815851
По шагам: 1. n^0.0769230769230769/52root8/52root4*52rootn 1.1. 1//13~~0.0769230769230769 1.00|1_3_ _ 9_1_|0.0769230769230769 90 7_8_ 120 1_1_7_ 30 2_6_ 40 3_9_ 100 9_1_ 90 7_8_ 120 1_1_7_ 30 2_6_ 40 3_9_ 100 9_1_ 90 7_8_ 120 1_1_7_ 3 2. n^0.0769230769230769/1.04079959637863/52root4*52rootn 2.1. 52root8=1.04079959637863 3. n^0.0769230769230769/1.04079959637863/1.02701805070877*52rootn 3.1. 52root4=1.02701805070877 4. n^0.0769230769230769/1.06891997265126*52rootn 4.1. 1.04079959637863*1.02701805070877~~1.06891997265126 X1.04079959637863 _ _ _ _ _ _ _ _ _ _ _ _ _ _1_._0_2_7_0_1_8_0_5_0_7_0_8_7_7_ _ 728559717465041 728559717465041 832639677102904 000000000000000 728559717465041 000000000000000 520399798189315 000000000000000 832639677102904 104079959637863 000000000000000 728559717465041 208159919275726 000000000000000 1_0_4_0_7_9_9_5_9_6_3_7_8_6_3_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 1.0689199726512551741967815851
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Answers & Comments
Выражение: 52root(n^4/8*m^2):52root(4*m^2/n)
Ответ: n^(1//13)/52root8/52root4*52rootn
Решаем по действиям:
1. 52root(n^4/8*m^2)=n^(1//13)/52root8*m^(1//26)
52root(n^4/8*m^2)=52root(n^4)/52root8*52root(m^2)
1.1. 52root(n^4)=n^(1//13)
1.2. 52root(m^2)=m^(1//26)
2. 52root(4*m^2/n)=52root4*m^(1//26)/52rootn
3. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn)=n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn
4. m^(1//26)/m^(1//26)=1
Решаем по шагам:
1. n^(1//13)/52root8*m^(1//26):52root(4*m^2/n)
1.1. 52root(n^4/8*m^2)=n^(1//13)/52root8*m^(1//26)
52root(n^4/8*m^2)=52root(n^4)/52root8*52root(m^2)
1.1.1. 52root(n^4)=n^(1//13)
1.1.2. 52root(m^2)=m^(1//26)
2. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn)
2.1. 52root(4*m^2/n)=52root4*m^(1//26)/52rootn
3. n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn
3.1. n^(1//13)/52root8*m^(1//26):(52root4*m^(1//26)/52rootn)=n^(1//13)/52root8*m^(1//26)/52root4/m^(1//26)*52rootn
4. n^(1//13)/52root8/52root4*52rootn
4.1. m^(1//26)/m^(1//26)=1
Приводим к окончательному ответу с возможной потерей точности:
Окончательный ответ: n^0.0769230769230769/1.06891997265126*52rootn
По действиям:
1. 1//13~~0.0769230769230769
1.00|1_3_ _
9_1_|0.0769230769230769
90
7_8_
120
1_1_7_
30
2_6_
40
3_9_
100
9_1_
90
7_8_
120
1_1_7_
30
2_6_
40
3_9_
100
9_1_
90
7_8_
120
1_1_7_
3
2. 52root8=1.04079959637863
3. 52root4=1.02701805070877
4. 1.04079959637863*1.02701805070877~~1.06891997265126
X1.04079959637863
_ _ _ _ _ _ _ _ _ _ _ _ _ _1_._0_2_7_0_1_8_0_5_0_7_0_8_7_7_ _
728559717465041
728559717465041
832639677102904
000000000000000
728559717465041
000000000000000
520399798189315
000000000000000
832639677102904
104079959637863
000000000000000
728559717465041
208159919275726
000000000000000
1_0_4_0_7_9_9_5_9_6_3_7_8_6_3_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
1.0689199726512551741967815851
По шагам:
1. n^0.0769230769230769/52root8/52root4*52rootn
1.1. 1//13~~0.0769230769230769
1.00|1_3_ _
9_1_|0.0769230769230769
90
7_8_
120
1_1_7_
30
2_6_
40
3_9_
100
9_1_
90
7_8_
120
1_1_7_
30
2_6_
40
3_9_
100
9_1_
90
7_8_
120
1_1_7_
3
2. n^0.0769230769230769/1.04079959637863/52root4*52rootn
2.1. 52root8=1.04079959637863
3. n^0.0769230769230769/1.04079959637863/1.02701805070877*52rootn
3.1. 52root4=1.02701805070877
4. n^0.0769230769230769/1.06891997265126*52rootn
4.1. 1.04079959637863*1.02701805070877~~1.06891997265126
X1.04079959637863
_ _ _ _ _ _ _ _ _ _ _ _ _ _1_._0_2_7_0_1_8_0_5_0_7_0_8_7_7_ _
728559717465041
728559717465041
832639677102904
000000000000000
728559717465041
000000000000000
520399798189315
000000000000000
832639677102904
104079959637863
000000000000000
728559717465041
208159919275726
000000000000000
1_0_4_0_7_9_9_5_9_6_3_7_8_6_3_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
1.0689199726512551741967815851