n = 2a + 3b
= 2(9, 4) + 3(-1, -2)
= (18, 8) + (-3, -6)
= (18 - 3, 8 - 6)
= (15, 2)
Отже, координати вектора n=2a+3b дорівнюють (15, 2).
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Answers & Comments
n = 2a + 3b
= 2(9, 4) + 3(-1, -2)
= (18, 8) + (-3, -6)
= (18 - 3, 8 - 6)
= (15, 2)
Отже, координати вектора n=2a+3b дорівнюють (15, 2).