№4 ((1/(m-1))-((m+1)/(m^2+m+1))):(1+(1/(n^3-1))). Created by Кристина20158. algebra-ru

(n^3-1)))...

Кристина20158 @Кристина20158

August 2021 1 7 Report

№4
((1/(m-1))-((m+1)/(m^2+m+1))):(1+(1/(n^3-1)))

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inblu

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$(\frac{1}{m-1}- \frac{m+1}{m^2+m+1}):(1+\frac{1}{m^3-1})= \\ =\frac{m^2+m+1-(m+1)(m-1)}{(m-1)(m^2+m+1)}}: \frac{m^3-1+1}{m^3-1}=\frac{m^2+m+1-m^2+1}{m^3-1}: \frac{m^3}{m^3-1}= \\ =\frac{m+2}{m^3-1}* \frac{m^3-1}{m^3}==\frac{m+2}{m^3}$

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