[tex]\displaystyle\bf\\(n+4)^{2} +3n^{2} =n^{2} +8n+16+3n^{2} =4n^{2} +8n+16 =\\\\\\=4\cdot(n^{2} +2n+4)[/tex]
Ответ : 4
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[tex]\displaystyle\bf\\(n+4)^{2} +3n^{2} =n^{2} +8n+16+3n^{2} =4n^{2} +8n+16 =\\\\\\=4\cdot(n^{2} +2n+4)[/tex]
Ответ : 4