На хлорирование алкилбензола было израсходовано 2,24л хлора и образовалось 14,05г монохлорпроизводного. Определите формулу алкилбензола.
C6H5-CnH2n+1 + Cl2= C6H5-CnH2nCl+HCl
n(Cl2)=0,1;
n(C6H5-CnH2nCl)=0,1;
M(C6H5-CnH2nCl)=14,05/0,1=140,5;
112,5+14n=140,5
n=2'
Ответ:C6H5-C2H5.
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Answers & Comments
C6H5-CnH2n+1 + Cl2= C6H5-CnH2nCl+HCl
n(Cl2)=0,1;
n(C6H5-CnH2nCl)=0,1;
M(C6H5-CnH2nCl)=14,05/0,1=140,5;
112,5+14n=140,5
n=2'
Ответ:C6H5-C2H5.
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