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dariaartymova
@dariaartymova
March 2022
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На какой высоте над поверхностью Земли сила тяготения уменьшается на 10 %? Радиус Земли считате 6400 км.
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MashaPutnaj
Verified answer
Дано F1=F F2=0,9*F h- ?
F1=G*m*M/R^2
F2=G*m*M/(R+h)^2
F1/F2=(R+h)^2/R^2=1/0,9=1.111111
(R+h)/R=1,234
h/R=0,234*6370=
h=0,37*6370=1494 км
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Verified answer
Дано F1=F F2=0,9*F h- ?F1=G*m*M/R^2
F2=G*m*M/(R+h)^2
F1/F2=(R+h)^2/R^2=1/0,9=1.111111
(R+h)/R=1,234
h/R=0,234*6370=
h=0,37*6370=1494 км