На рисунке изображен график линейной функции y = kx + b. Чему равен коэффициент k ?. Created by ЯроликаОтличница. algebra-ru

По графику определим две точки, принадлежащие данной прямой y=kx+b.А(-3;2) и В(-2;-4)Подставим их координаты в уравнение функции y=kx+b:{-3k+b=2{-2k+b=-4{b=2+3k{b=-4+2k => 2+3k=-4+2k 3k-2k=-4-2 k=-6Ответ: k=-6Новые вопросы в Алгебра5 завдання, поможіть пжДАЮ 85 БАЛОВ. РЕШИТЕ ПОЖАЛУЙСТА ДО 20:00. УМОЛЯЮ !!!Выполнить только кружочки!!!Решите это методом графичным или методом добавки Помогите пожалуйста. 1 вычислите:0,6√324+3√0,812разложите на множители: 10-2√¹0пж пж пж пж срочно надо надо только 5 задание пж пж пж пж срочно надо пж срочно надо пж пж пж пжПожалуйста помогите. Найдите значение выражения еслиа=5, b=2:a²-b²———(a-b)Ответы:а)7;б)3;в)21;г)-3.Пожалуйста помогите. Известно что a<ba<b какое из утверждений неверное? а)a-3>b-3 a-3б)3a<3b 3a<3bв)-3a>-3b-3a>-3bГ)a+3<b+3a+3…<b+3У трикутнику АВС відомо, що кут С=90* , ВС=15 см, АВ=25 см. Чому дорівнює sin A?ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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На рисунке изображен график линейной функции y = kx + b. Чему равен коэффициент ...

ЯроликаОтличница @ЯроликаОтличница

June 2022 1 4 Report

На рисунке изображен график линейной функции y = kx + b. Чему равен коэффициент k ?

Answers & Comments

Эксперт5

Verified answer

По графику определим две точки, принадлежащие данной прямой y=kx+b.
А(-3;2) и В(-2;-4)
Подставим их координаты в уравнение функции y=kx+b:
{-3k+b=2
{-2k+b=-4

{b=2+3k
{b=-4+2k => 2+3k=-4+2k
3k-2k=-4-2
k=-6
Ответ: k=-6