V1=2 м3 V1=2 м3 Δр12=7,5-3=4,5*10^6 Па ΔV=8-2=6 м3 р2=7,5*10^6 Па Q=?
Q=Q12+Q23
1-2 Изохора 2-3 изобара
Q12=(3/2)*Δp12*V1 Q23=(5/2)*p2*ΔV
Q=(3/2)*4.5*10^6*2+(5/2)*7.5*10^6*6=126*10^6 Дж (126 МДж)
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V1=2 м3 V1=2 м3 Δр12=7,5-3=4,5*10^6 Па ΔV=8-2=6 м3 р2=7,5*10^6 Па Q=?
Q=Q12+Q23
1-2 Изохора 2-3 изобара
Q12=(3/2)*Δp12*V1 Q23=(5/2)*p2*ΔV
Q=(3/2)*4.5*10^6*2+(5/2)*7.5*10^6*6=126*10^6 Дж (126 МДж)
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