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kukuku007
@kukuku007
July 2022
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надо очень срочнооооооооо
6-10cos^2X+4cos2X=sin2X
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sedinalana
Verified answer
6sin²x+6cos²x-10cos²x+4cos²x-4sin²x-2sinxcosx=0
2sin²x-2sinxcosx=0
2sinx(sinx-cosx)=0
sinx=0⇒x=πn,n∈z
sinx-cosx=0/cosx
tgx-1=0
tgx=1
x=π/4+πn,n∈z
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Thanks 4
kukuku007
помоги еще плииз cos^2(pi/2+x)-cos^2(2pi+x)=корень из 3 на 2
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Answers & Comments
Verified answer
6sin²x+6cos²x-10cos²x+4cos²x-4sin²x-2sinxcosx=02sin²x-2sinxcosx=0
2sinx(sinx-cosx)=0
sinx=0⇒x=πn,n∈z
sinx-cosx=0/cosx
tgx-1=0
tgx=1
x=π/4+πn,n∈z