Надо решить уравнение >.< я не могу его решить ':(. Created by LittleGnomeAru. algebra-ru

√(x+7) * √(3x-2) = 3√(x-1) * √(x+2){x+7≥0{3x-2≥0{x-1≥0{x+2≥0{x≥-7{x≥2/3{x≥1{x≥-2x≥1√[(x+7)(3x-2)] = √[9(x-1)(x+2)](x+7)(3x-2)=9(x-1)(x+2)3x²+21x-2x-14=9(x²-x+2x-2)3x²+19x-14=9x²+9x-183x²-9x²+19x-9x-14+18=0-6x²+10x+4=03x²-5x-2=0D=25+4*3*2=25+24=49x₁=5-7= -2/6 =-1/3 - не подходит, т.к. х≥1 6х₂=5+7=2 6Ответ: D) 2. спасибо огромное ^•^ Реклама Реклама Новые вопросы в Алгебра Знайдіть a , якщо остача від ділення Px=x3-ax2+6x+2; на Qx=x-2 дорівнює R=2 Розкладіть многочлен Px=x3+6x2-13x-42 на множники. -3x^2 + 5x + 2 РАЛОЖИТЕ НА МНОЖИТЕЛИ ПЕРВОЙ СТЕПЕНИ 35 БАЛЛОВ помогите 7 и 8 пожалуйста!!! помогите найти ответы срочно!!! помогите найти ответы дам 50 балов!!! По графику определите а) нули функции б)промежутки на которых функция принимает положительные значения и отрицательные значения в) промежутки возраста … ния и убывания функции Помогите, пожалуйста. lim √x-3-√9-x/x-6х→6 Вычислите !ЗАДАНИЕ НА ФОТО Игральную кость бросили один или несколько раз. Оказалось, что сумма всех выпавших очков равна 4. Какова вероятность того, что был сделан один бросок? … Ответ округлите до сотых. Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Надо решить уравнение >.< я не могу его решить ':(...

LittleGnomeAru @LittleGnomeAru

November 2021 1 11 Report

Надо решить уравнение >.< я не могу его решить ':(

Answers & Comments

m11m √(x+7) * √(3x-2) = 3√(x-1) * √(x+2)

{x+7≥0
{3x-2≥0
{x-1≥0
{x+2≥0

{x≥-7
{x≥2/3
{x≥1
{x≥-2

x≥1

√[(x+7)(3x-2)] = √[9(x-1)(x+2)]
(x+7)(3x-2)=9(x-1)(x+2)
3x²+21x-2x-14=9(x²-x+2x-2)
3x²+19x-14=9x²+9x-18
3x²-9x²+19x-9x-14+18=0
-6x²+10x+4=0
3x²-5x-2=0
D=25+4*3*2=25+24=49
x₁=5-7= -2/6 =-1/3 - не подходит, т.к. х≥1
6
х₂=5+7=2
6
Ответ: D) 2.