Нахождение значения функции по значению аргумента и наоборот. Урок 1 Установи соответствия.
f(x) = 4x2 + 2x + 5
f(x) = –4x2 + 2x – 5
f(x) = 0,5x2 – 5x + 3
f(x) = –0,5x2 + 5x + 3
f(x) = –2x2 + 8x – 3
f(x) = 2x2 + 8x + 3
f (–2) = 15
f (–2) = –9
f (–2) = 17
f (–2) = –25
f (–2) = –5
f (–2) = –27
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f(x) = 4x2 + 2x + 5
f(x) = –4x2 + 2x – 5
f(x) = 0,5x2 – 5x + 3
f(x) = –0,5x2 + 5x + 3
f(x) = –2x2 + 8x – 3
f(x) = 2x2 + 8x + 3
f (–2) = 15
f (–2) = –9
f (–2) = 17
f (–2) = –25
f (–2) = –5
f (–2) = –27
Назад
Проверить
срочнооо
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