Ответ:
max{x^3 - 3 x^2 + 5|-1<=x<=3} = 5 at x = 0
max{x^3 - 3 x^2 + 5|-1<=x<=3} = 5 at x = 3
min{x^3 - 3 x^2 + 5|-1<=x<=3} = 1 at x = -1
min{x^3 - 3 x^2 + 5|-1<=x<=3} = 1 at x = 2
Объяснение:
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Ответ:
max{x^3 - 3 x^2 + 5|-1<=x<=3} = 5 at x = 0
max{x^3 - 3 x^2 + 5|-1<=x<=3} = 5 at x = 3
min{x^3 - 3 x^2 + 5|-1<=x<=3} = 1 at x = -1
min{x^3 - 3 x^2 + 5|-1<=x<=3} = 1 at x = 2
Объяснение: