3(x - 2) - 7 ≥ 2(x - 3)
3x - 6 - 7 ≥ 2x - 6
3x - 2x ≥ - 6 + 6 + 7
x ≥ 7
x ∈ [7 ; + ∞)
Ответ: наименьшее целое 7
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3(x - 2) - 7 ≥ 2(x - 3)
3x - 6 - 7 ≥ 2x - 6
3x - 2x ≥ - 6 + 6 + 7
x ≥ 7
x ∈ [7 ; + ∞)
Ответ: наименьшее целое 7