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shkohp
@shkohp
July 2022
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Найди корни квадратного трехчлен
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KarinaYouchi
А)x^2-5x+6=0
x1*x2=6
x1+x2=5
x1=3
x2=2
б)-x^2+2x+99=0 |*(-1)
x^2-2x-99=0
x1*x2=-99
x1+x2=2
x1=-9
x2=11
в)2x^2-x-6=0
D=(-1)^2-4*2*(-6)=1+48=49
x1=1+√49=1+7=8\4=2
2*2 4
x1=1-√49=1-7=-6\4=-3\2=-1.5
2*2 4
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Answers & Comments
x1*x2=6
x1+x2=5
x1=3
x2=2
б)-x^2+2x+99=0 |*(-1)
x^2-2x-99=0
x1*x2=-99
x1+x2=2
x1=-9
x2=11
в)2x^2-x-6=0
D=(-1)^2-4*2*(-6)=1+48=49
x1=1+√49=1+7=8\4=2
2*2 4
x1=1-√49=1-7=-6\4=-3\2=-1.5
2*2 4