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Азяка21
@Азяка21
June 2022
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Найди корни квадратного уравнения x(в квадрате)+7x+12=0
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007gaglik
X2+7x+12=0
D=7^2-4×1×12=49-48=1
x1=-7+1/2×1=-6/2=-3
x2=-7-1/2×1=-8/2=-4
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Азяка21
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Answers & Comments
D=7^2-4×1×12=49-48=1
x1=-7+1/2×1=-6/2=-3
x2=-7-1/2×1=-8/2=-4