найди корни уравнения: z^2+19z+60=0. Created by miliolia125. algebra-ru

найди корни уравнения: z^2+19z+60=0...

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$z^2+19z+60=0\\
D=19^2-4*60=121=11^2\\
z_1= \frac{-19-11}{2}=-15\\ z_2= \frac{-19+11}{2}=-4$

3 votes Thanks 1

BETTELGEUSE Z²+19z+60=0.
z1,2=(-19±√(19²-4•60))/2.
z1,2=(-19±√(361-240))/2.
z1,2=(-19±√121)/2.
z1,2=(-19±11)/2.
z1=-15.
z2=-4
проверка.
(z+15)(z+4)=0.
z²+4z+15z+60=0.
z²+19z+60=0.

4 votes Thanks 1

miliolia125 извини, можешь помочь с еще одним заданием?

miliolia125 Разложить это на множители: xz^12+xh^12−hz^12−h^13

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