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Tatianakis
@Tatianakis
August 2022
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Найдите 5 cos 2α,если sin α = -0,4
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LFP
Verified answer
5cos(2a) = 5(cos²(a) - sin²(a)) = 5(1 - 2sin²(a)) = 5 - 10*(-0.4)² = 5 - 1.6 = 3.4
1 votes
Thanks 3
Tatianakis
Большое спасибо)
mitirew
Cos2a=1-2sin^2a
5 cos 2α=5(
1-2sin^2a)=5(1-2*(-0.4^2))=5(1-0.32)=5*0.68=-3.4
0 votes
Thanks 0
mitirew
без минуса ответ опечатка)
Tatianakis
Спасибо)
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Verified answer
5cos(2a) = 5(cos²(a) - sin²(a)) = 5(1 - 2sin²(a)) = 5 - 10*(-0.4)² = 5 - 1.6 = 3.45 cos 2α=5(1-2sin^2a)=5(1-2*(-0.4^2))=5(1-0.32)=5*0.68=-3.4