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234Masha234
@234Masha234
July 2022
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найдите а1 и d в арифметической прогрессии, в которой система:
а2*а4 = -5
а5 - а3 = -6
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DariosI
Verified answer
Выразим всю систему через а2
а4=а2+2d
a3=a2+d
a5=a2+3d
a5-a3=a2+3d-a2-d=2d=-6
d=-6/2=-3
a2*a4=a2*(a2+2d)=a2 (a2-6)=a2 ^2-6a2
a2 ^2-6a2=-5
a2 ^2-6a2+5=0
D=6^2-4*5=16
a2=(6-4)/2=1
a1=a2-d=1+3=4
a2=(6+4)/2=5
a1=a2-d=5+3=8
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Answers & Comments
Verified answer
Выразим всю систему через а2а4=а2+2d
a3=a2+d
a5=a2+3d
a5-a3=a2+3d-a2-d=2d=-6
d=-6/2=-3
a2*a4=a2*(a2+2d)=a2 (a2-6)=a2 ^2-6a2
a2 ^2-6a2=-5
a2 ^2-6a2+5=0
D=6^2-4*5=16
a2=(6-4)/2=1
a1=a2-d=1+3=4
a2=(6+4)/2=5
a1=a2-d=5+3=8