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ironwoman9
@ironwoman9
July 2022
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найдите целые корни уравнения (x-3)*(6+x)*(x^2 - 2x-8) = 126x^2
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kusnarsity1998
Первый корень находим методом подбора. он равен 1
X^4+x^3-6X^2-4X+8=(х-1)*(x^3+2x^2-4x-8) Следующий корень опять-таки подбором -2
(х-1)(х+2)((х-2)(х+2)=0 третий корень х=2
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Answers & Comments
X^4+x^3-6X^2-4X+8=(х-1)*(x^3+2x^2-4x-8) Следующий корень опять-таки подбором -2
(х-1)(х+2)((х-2)(х+2)=0 третий корень х=2