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@113020021
July 2022
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Найдите число членов и сумму арифметической прогрессии:2; 4; ...;2n-4;
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Удачник66
Verified answer
A1= 2; d = 2
a(n) = a1 + d(n-1) = 2 + 2(n - 1) = 2n
2n - 4 = a(n-2), то есть (n-2)-ой член прогрессии.
Сумма (n-2) членов:
S(n-2) = (a1 + a(n-2))*(n-2)/2 = (2+2n-4)(n-2)/2 = (2n-2)(n-2)/2 = n^2-3n+2
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Answers & Comments
Verified answer
A1= 2; d = 2a(n) = a1 + d(n-1) = 2 + 2(n - 1) = 2n
2n - 4 = a(n-2), то есть (n-2)-ой член прогрессии.
Сумма (n-2) членов:
S(n-2) = (a1 + a(n-2))*(n-2)/2 = (2+2n-4)(n-2)/2 = (2n-2)(n-2)/2 = n^2-3n+2