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Skill455
@Skill455
July 2022
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Найдите Cosa,tga,ctga, если известно,что sina=-3 корень из одиннадцати, разделить на 10 и a принадлежит (1,5p;2p)
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sedinalana
Verified answer
Cosa=√1-sin²a)=√(1-99/100)=√(1/100=1/10
tga=sina/cosa=1/10:(-3√11/10)=-1/10*10/3√11=-1/3√11=-√11/33
ctga=1/tga=1:(1/3√11)=-3√11
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Verified answer
Cosa=√1-sin²a)=√(1-99/100)=√(1/100=1/10tga=sina/cosa=1/10:(-3√11/10)=-1/10*10/3√11=-1/3√11=-√11/33
ctga=1/tga=1:(1/3√11)=-3√11