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jennybe1312
@jennybe1312
July 2022
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найдите диаметр окружности описанной около треугольника авс bc = 2√2 , А = 45°
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matalhim
BC/sin45 = 2R
BC/sin45 = D
D=4
3 votes
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Answers & Comments
BC/sin45 = D
D=4