найдите градусную меру угла поворота заданного в радианах. Created by iminovil2004. algebra-ru

найдите градусную меру угла поворота заданного в радианах...

iminovil2004 @iminovil2004

July 2022 1 7 Report

найдите градусную меру угла поворота заданного в радианах

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$\pi =180^\circ \\\\a)\ \ \dfrac{\pi}{3}=\dfrac{180^\circ }{3}=60^\circ \ \ ,\ \ \ \dfrac{\pi}{2}=\dfrac{180^\circ}{2}=90^\circ \ \ ,\ \ -\dfrac{2\pi}{3}=-\dfrac{2\cdot 180^\circ }{3}=-120^\circ \ ,\\\\{}\ \ \ \ \dfrac{3\pi }{4}=\dfrac{3\cdot 180^\circ }{4}=135^\circ \\\\\\b)\ \ -\dfrac{3\pi}{2}=-\dfrac{3\cdot 180^\circ }{2}=-270^\circ \ \ ,\ \ \dfrac{\pi}{12}=\dfrac{180^\circ }{12}=15^\circ \ \ ,\\\\{}\ \ \ \ \ \ \dfrac{4\pi}{9}=\dfrac{4\cdot 180^\circ }{9}=80^\circ \ \ ,\ \ -3\pi =-3\cdot 180^\circ =-540$

$c)\ \ -\pi =-180^\circ \ \ ,\ \ \ \dfrac{\pi}{18}=\dfrac{180^\circ }{19}=10^\circ \ \ ,\ \ \ -\dfrac{5}{6}\, \pi =-\dfrac{5\cdot 180^\circ }{6}=-150^\circ \ \ ,\\\\{}\ \ \ \ \ \dfrac{\pi}{36}=\dfrac{180^\circ }{36}=5^\circ$

$d)\ \ 1\ radian=\dfrac{180^\circ }{\pi }\approx 57,3^\circ \\\\2=\dfrac{2\cdot 180^\circ }{\pi }=\dfrac{360^\circ }{\pi }\approx 114,6^\circ \ \ ,\ \ \ -3=-\dfrac{3\cdot 180^\circ }{\pi }=-\dfrac{540^\circ }{\pi }\approx -171,9^\circ \ \ ,\\\\2,5=\dfrac{2,5\cdot 180^\circ }{\pi }=\dfrac{450^\circ }{\pi }\approx 143,3^\circ \ \ \,\ \ \ -15=-\dfrac{15\cdot 180^\circ }{\pi }=\dfrac{2700^\circ }{\pi }\approx 859,5^\circ$

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