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nastuakirucova
@nastuakirucova
October 2021
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Найдите координаты середины отрезка АВ , если А(-5;3) , В(-2;4)
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k1598
АВ(х;у)
х=х1+х2/2
у=у1+у2/2
х= -5+(-2)/2= -7/2= -3,5
у=3+4/2= 7/2=3,5
АВ(-3,5; 3,5)
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Answers & Comments
х=х1+х2/2
у=у1+у2/2
х= -5+(-2)/2= -7/2= -3,5
у=3+4/2= 7/2=3,5
АВ(-3,5; 3,5)