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mixailsv04
@mixailsv04
July 2022
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найдите координаты точек пересечения параболы y=3x^2+13x-10 c осями координат
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ShirokovP
Verified answer
Y = 3x^2 + 13x - 10
ось абсцисс
3x^2 + 13x - 10 = 0
D = 169 + 120 = 289
x1 = ( - 13 + 17)/6 = 2/3
x2 = ( - 13 - 17)/6 = - 5
( - 5; 0 ) ; ( 2/3; 0)
ось ординат
y (0) = 3*0 + 13*0 - 10 = - 10
( 0; - 10)
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Answers & Comments
Verified answer
Y = 3x^2 + 13x - 10ось абсцисс
3x^2 + 13x - 10 = 0
D = 169 + 120 = 289
x1 = ( - 13 + 17)/6 = 2/3
x2 = ( - 13 - 17)/6 = - 5
( - 5; 0 ) ; ( 2/3; 0)
ось ординат
y (0) = 3*0 + 13*0 - 10 = - 10
( 0; - 10)