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ILOVEYOU99
@ILOVEYOU99
July 2022
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Найдите координаты точки пересечения графиков функций y=x^2+8x-5 и y=2x^2+10x-8
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qwerty1109
2х^2+10х-8=х^2+8х-5
2х^2+10х-8-х^2-8х+5=0
х^2+2х-3=0
D=4+12=16
x1=(-2+4)/2=1
x2=-3
Y1=4
Y2=-20
Ответ(1;4)(-3;-20)
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Answers & Comments
2х^2+10х-8-х^2-8х+5=0
х^2+2х-3=0
D=4+12=16
x1=(-2+4)/2=1
x2=-3
Y1=4
Y2=-20
Ответ(1;4)(-3;-20)