Найдите координаты точки пересечения медиан треугольника ABC, если A(3; 6) В(6;-2) С(-2;6)
AB: (x-0)/(3-0)=(y-1)/(5-1) => 4x=3y-3 => 4x-3y+3=0. CE: (x-6)/4=(y-0)/(-3) => -3x+18=4y =>3x+4y-18=0. D: x=(3+6)/2=9/2; y=(5+0)/2=5/2; AD: (x-0)/(9/2-0).
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
AB: (x-0)/(3-0)=(y-1)/(5-1) => 4x=3y-3 => 4x-3y+3=0. CE: (x-6)/4=(y-0)/(-3) => -3x+18=4y =>3x+4y-18=0. D: x=(3+6)/2=9/2; y=(5+0)/2=5/2; AD: (x-0)/(9/2-0).