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neznaika222
@neznaika222
July 2022
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найдите корень уравнение
(х+2)+х=9
х+(7+х)=11
х+2х-5=40
х+(4+х)+х=16
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lentomsk
1)(х+2)+х=9
х+2+х=9
2х=9-2
2х=7
х=9:2
х=4,5
2)х+(7+х)=11
х+7+х=11
2х=11-7
2х=4
х=4:2
х=2
3)х+2х-5=40
3х=40+5
3х=45
х=45:3
х=15
4)х+(4+х)+х=16
х+4+х+х=16
3х=16-4
3х=12
х=12:3
х=4
1 votes
Thanks 2
lgolovizina
(х+2)+х=9 х +(7+х)=11 х+2х-5 = 40
2х=7 2х=11-7 3х = 45
х = 7/2 х = 4/2 х =45:3
х = 3 1/2 х = 2 х = 15
х + (4+х) +х = 16
х+4+х+х = 16
3х = 16-4
3х=12
х=12:3
х = 4
3 votes
Thanks 2
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Answers & Comments
х+2+х=9
2х=9-2
2х=7
х=9:2
х=4,5
2)х+(7+х)=11
х+7+х=11
2х=11-7
2х=4
х=4:2
х=2
3)х+2х-5=40
3х=40+5
3х=45
х=45:3
х=15
4)х+(4+х)+х=16
х+4+х+х=16
3х=16-4
3х=12
х=12:3
х=4
2х=7 2х=11-7 3х = 45
х = 7/2 х = 4/2 х =45:3
х = 3 1/2 х = 2 х = 15
х + (4+х) +х = 16
х+4+х+х = 16
3х = 16-4
3х=12
х=12:3
х = 4