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hall2
@hall2
July 2022
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найдите корни биквадратного уравнения х⁴+ х²-2=0
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Support001
X^4+x^2-2=0
x^2=t
t^2+t-2=0
D=1-4*(-2)=9
t1,2= -1+/-3/2
t1 = -2 t2=1
x^2=1 x = 1
x^2 = -2 - не подходит.
Ответ: x = +-1
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Answers & Comments
x^2=t
t^2+t-2=0
D=1-4*(-2)=9
t1,2= -1+/-3/2
t1 = -2 t2=1
x^2=1 x = 1
x^2 = -2 - не подходит.
Ответ: x = +-1