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лиза6100
@лиза6100
August 2021
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найдите корни квадратного трехчлена: 1)х^2-10х+9 2)5х^2+12х+4
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Answers & Comments
Zhorahis2000
1) x
²-10x+9 = 0
a =1; b = -10; c=9
D = b²-4ac
D = (-10)²- 4 ·9 = 100 - 36 = 64(√64=8)
x1 = -b+√D/2a ⇒ -(-10)+8/2 = 18/2 =
9
.
x2 = -b-√D/2a ⇒ -(-10) -8/2 = 2/2 =
1
.
2) 5x²+12x+4 = 0
a=5; b=12; c=4
D = b²-4ac
D = 12² - 4·5·4 = 144 - 80 = 64 (√64=8)
x1 = -b+√D/2a ⇒ -12+8/2·5 = -4/10 =
-0,4
.
x2 = -b-√D/2a ⇒ -12-8/2·5 = -20/10 =
-2
.
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Answers & Comments
a =1; b = -10; c=9
D = b²-4ac
D = (-10)²- 4 ·9 = 100 - 36 = 64(√64=8)
x1 = -b+√D/2a ⇒ -(-10)+8/2 = 18/2 = 9.
x2 = -b-√D/2a ⇒ -(-10) -8/2 = 2/2 = 1.
2) 5x²+12x+4 = 0
a=5; b=12; c=4
D = b²-4ac
D = 12² - 4·5·4 = 144 - 80 = 64 (√64=8)
x1 = -b+√D/2a ⇒ -12+8/2·5 = -4/10 = -0,4.
x2 = -b-√D/2a ⇒ -12-8/2·5 = -20/10 = -2.