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sasha220volt
@sasha220volt
September 2021
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найдите корни квадратного трехчлена 4b2-16b+12
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Шаен
4b^2-16b+12=0
D=(-16)^2-4*4*12=256-192=64
b1=16+8/8=3
b2=16-8/8=1
1 votes
Thanks 3
meowizzi
4b^2-16b+12=0 |:4
b^2-4b+3=0
D=b^2-4ac=16-12=4
b=-b+-d^(1/2)/2a
b1=4-2/2=2/2=1
b2=4+2/2=3
b1=1
b2=3
2 votes
Thanks 1
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Answers & Comments
D=(-16)^2-4*4*12=256-192=64
b1=16+8/8=3
b2=16-8/8=1
b^2-4b+3=0
D=b^2-4ac=16-12=4
b=-b+-d^(1/2)/2a
b1=4-2/2=2/2=1
b2=4+2/2=3
b1=1
b2=3