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ami110
@ami110
November 2021
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найдите корни квадратного уравнения
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елена1811
D=37.21+64.8=102.01
x1=-6.1+10.1/6=2/3
x2=-6.1-10.1/6=2.7
0 votes
Thanks 1
NadDer
3х²+6,1х-5,4 = 0
D = 37,21 +64,8 = 102,01
√D = 10,1
х1 = (-6,1+10,1):6 =
2\3
х2 = (-6,1-10,1):6 = -16,2:6 =
-2,7
1 votes
Thanks 2
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Answers & Comments
x1=-6.1+10.1/6=2/3
x2=-6.1-10.1/6=2.7
D = 37,21 +64,8 = 102,01
√D = 10,1
х1 = (-6,1+10,1):6 = 2\3
х2 = (-6,1-10,1):6 = -16,2:6 =-2,7