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groznaya971
@groznaya971
September 2021
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Найдите корни трехчлена.
1) 12х^2-4х-5.
2)5х^2+9х-2.
3)4х^2-64
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9379992bat
12²x-4x-5=0
D=(4)²-4*12*-5=16+240=√256=16
x1=4+16/2*12=20/24=5/6
x2=4-16/2*12=-12/24=-1/2
5x²+9x-2=0
D=9²-4*5*-2=81+40=√121=11
x1=-9+11/2*5=2/10=1/5
x2=-9-11/2*5=-20/10=-2
4x²-64=0
4(x²-16)=0
x²-16=0
x=+4. -4 и 4≠0
4 votes
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Answers & Comments
D=(4)²-4*12*-5=16+240=√256=16
x1=4+16/2*12=20/24=5/6
x2=4-16/2*12=-12/24=-1/2
5x²+9x-2=0
D=9²-4*5*-2=81+40=√121=11
x1=-9+11/2*5=2/10=1/5
x2=-9-11/2*5=-20/10=-2
4x²-64=0
4(x²-16)=0
x²-16=0
x=+4. -4 и 4≠0