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dmitrijMsk
@dmitrijMsk
July 2022
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Найдите корни уравнений.(Пож - та распишите подробнее.)
(3х + 2)(х - 4) = 0
(х - 2) в квдр. - 1=0
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katerina1177q
1) 3х в квадрате -12х+2х-8=0; 3х в кв.-10х-8=0; х 1,2= 10+/-(100-4*3*(-8))/2=10+/-(100-96)/2;10 +/- 4 /2; х1= 10+4/2=7;х2=10-4/2=3
2) (х-2) в кв.-1; х2-4х+4-1=0; х2-4х+3=0; х1+х2=4; х1*х2=3; х1=3; х2=1
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Answers & Comments
2) (х-2) в кв.-1; х2-4х+4-1=0; х2-4х+3=0; х1+х2=4; х1*х2=3; х1=3; х2=1