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polinka8855
@polinka8855
July 2022
1
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Найдите корни уравнения:
1) 7+2х²=2(х+1)(х+3);
2) (у+4)(у+1)=у-(у-2)(2-у).
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yandexgoogle
1. 7+2x²=2(x
²+x+3x+3)
7+2x
²=2x
²+2x+6x+6
7-2x-6x=6
-8x=-1
x=1/8
2. y
²+4y+y+4=y²-3y+4
4y+3y+y=0
y=0
1 votes
Thanks 5
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Answers & Comments
7+2x²=2x²+2x+6x+6
7-2x-6x=6
-8x=-1
x=1/8
2. y²+4y+y+4=y²-3y+4
4y+3y+y=0
y=0