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Tanechka3798
@Tanechka3798
August 2022
2
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найдите корни уравнения 2х²-13х+11=0
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MrBrain11
D=(13)^2-(4)2*11=81=9^2
x1,2=13+-9/4. x1=5,5. x2=1
0 votes
Thanks 1
нико14
2х^2-13х+11=0
D=b^2-4ac=(-13)^2-4*2*11=
169-88=81
х1=
-b+√D/2a=13+9/4=22/4=5,5
x2=-b-√D/2a=13-9/4=1
2 votes
Thanks 1
Tanechka3798
спасибо большое
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Answers & Comments
x1,2=13+-9/4. x1=5,5. x2=1
D=b^2-4ac=(-13)^2-4*2*11=
169-88=81
х1=
-b+√D/2a=13+9/4=22/4=5,5
x2=-b-√D/2a=13-9/4=1