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mariya260464
@mariya260464
August 2022
1
6
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Найдите корни уравнения ,3tgx=√ 3 принадлежащий отрезку [0;2π]
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TMuhriddin
3tgx=3^1/2. tgx=3^(1/2)/3
x=П/6+ПК
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x=П/6+ПК