Найдите корни уравнения:
a)4x^2-4x+1=0, D=b^2-4ac==16-4*4*1=0, x=-b/2a=4/2*4=4/8=1/2
b) 5y^2+20y+20=0,D=b^2-4ac=400-4*5*20=0, y=-b/2a=-20/2*5=-2
(2х-1)(2х-1)=0
4х2-2х-2х+1=0
4х2-4х+1=0
Д=16-16=0
х=-б/2а=4/8
х=0,5
5у2+20у+20=0
Д=400-400=0
х=-20/10=-2
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Verified answer
a)4x^2-4x+1=0, D=b^2-4ac==16-4*4*1=0, x=-b/2a=4/2*4=4/8=1/2
b) 5y^2+20y+20=0,D=b^2-4ac=400-4*5*20=0, y=-b/2a=-20/2*5=-2
Verified answer
(2х-1)(2х-1)=0
4х2-2х-2х+1=0
4х2-4х+1=0
Д=16-16=0
х=-б/2а=4/8
х=0,5
5у2+20у+20=0
Д=400-400=0
х=-20/10=-2