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Augest
@Augest
August 2022
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найдите корни уравнения
(x+1)^2-1+2x=0
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Kalderone
(x+1)²-1+2x=0
x²+2x+1-1+2x=0
x²+4x=0
x(x+4)=0
x=0;x=-4
0 votes
Thanks 1
Alishha
(x+1)^2-1+2x=0
x^2+2x+1-1+2x=0
+1-1 сокращаться, отстаеться:
x^2+4x=0
x(x+4)=0
x1=0 x+4=0
Ответ: x1=0 x2=-4
0 votes
Thanks 1
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Answers & Comments
x²+2x+1-1+2x=0
x²+4x=0
x(x+4)=0
x=0;x=-4
x^2+2x+1-1+2x=0
+1-1 сокращаться, отстаеться:
x^2+4x=0
x(x+4)=0
x1=0 x+4=0
Ответ: x1=0 x2=-4